x^2+16x+20=0

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Solution for x^2+16x+20=0 equation:


Simplifying
x2 + 16x + 20 = 0

Reorder the terms:
20 + 16x + x2 = 0

Solving
20 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + 16x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + 16x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 16x + x2 = 0 + -20
16x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
16x + x2 = -20

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -20 + 64

Reorder the terms:
64 + 16x + x2 = -20 + 64

Combine like terms: -20 + 64 = 44
64 + 16x + x2 = 44

Factor a perfect square on the left side:
(x + 8)(x + 8) = 44

Calculate the square root of the right side: 6.633249581

Break this problem into two subproblems by setting 
(x + 8) equal to 6.633249581 and -6.633249581.

Subproblem 1

x + 8 = 6.633249581 Simplifying x + 8 = 6.633249581 Reorder the terms: 8 + x = 6.633249581 Solving 8 + x = 6.633249581 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 6.633249581 + -8 Combine like terms: 8 + -8 = 0 0 + x = 6.633249581 + -8 x = 6.633249581 + -8 Combine like terms: 6.633249581 + -8 = -1.366750419 x = -1.366750419 Simplifying x = -1.366750419

Subproblem 2

x + 8 = -6.633249581 Simplifying x + 8 = -6.633249581 Reorder the terms: 8 + x = -6.633249581 Solving 8 + x = -6.633249581 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -6.633249581 + -8 Combine like terms: 8 + -8 = 0 0 + x = -6.633249581 + -8 x = -6.633249581 + -8 Combine like terms: -6.633249581 + -8 = -14.633249581 x = -14.633249581 Simplifying x = -14.633249581

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.366750419, -14.633249581}

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